सदिश `vecF=4hati-3hatk` के लंबवत सदिश है :

A force vecF=4hati-5hatj+3hatk N is acting on a point vecr_1=2hati+4hatj+3hatk m. The torque acting about a point vecr_2=4hati-3hatk m is

A force vecF=4hati-5hatj+3hatk N is acting on a point vecr_1=2hati+4hatj+3hatk m. The torque acting about a point vecr_2=4hati-3hatk m is

Following three forces keep a body in equilibrium. vecF_1=hati+3hatj+2hatk , vecF_2=3hati-4hatk and vecF_3=ahati-3hatj+2hatk , then the value of a is

Let vecF=2hati+4hatj+3hatk at the point P with position vector hati-hatj+3hatk . Find the moment of vecF about the line through the origin O in the direction of the vector veca=hati+2hatj+2hatk .

A force vecF=3hati+chatj+2hatk acting on a particle causes a displacement vecd=-4hati+2hatj-3hatk . If the work done is 6 J. then the value of c will be

Find the angle between the force vecF=(2hati+3hatj-hatk) unit and the displacement vecd=(3hati+4hatj+2hatk) unit. Also find the projection of vecF on vecd .

Following forces start acting on a particle at rest at the origin of the co-ordiante system simultaneously vecF_1=-4hati-4hatj+5hatk , vacF_2=5hati+8hatj+6hatk , vecF_3=-3hati+4hatj-7hatk and vecF_4=2hati-3hatj-2hatk then the particle will move