The identical metal spheres A and B are supported on insulating stands and placed in contact . What kind of charges will A and B develop when a negatively charged ebonite rod is brought near A ?

Options

A. A will hae a positive charge and B will have a negative charge
B. A will have a negative charge and B will have a positive charge
C. Both A and B will have positive charges
D. Both A and B will have negative charge

Explanation

To solve the problem, we need to analyze the situation step by step:

### Step 1: Understanding the Setup
We have two identical metal spheres, A and B, that are in contact with each other and are supported on insulating stands. This means that they cannot exchange charge with the ground or any other object.

**Hint:** Identify the properties of the objects involved (spheres, ebonite rod) and their arrangement.

### Step 2: Bringing the Negatively Charged Rod Near Sphere A
When a negatively charged ebonite rod is brought near sphere A, it will induce a charge separation in the spheres due to electrostatic induction. The negative charge of the rod will repel the electrons in sphere A.

**Hint:** Consider the effect of the electric field created by the negatively charged rod on the nearby charges in the spheres.

### Step 3: Charge Induction on Sphere A
As the negatively charged rod approaches sphere A, the electrons in sphere A will be repelled away from the rod. This will leave sphere A with a net positive charge because there are fewer electrons in that region.

**Hint:** Think about how charges move in response to an external electric field.

### Step 4: Charge Induction on Sphere B
Since spheres A and B are in contact, the positive charge that has developed on sphere A will influence sphere B. The electrons in sphere B will move towards sphere A to neutralize some of the positive charge. This will leave sphere B with a net negative charge.

**Hint:** Remember that charges can move between conductors that are in contact.

### Step 5: Final Charge Distribution
After the negatively charged rod is brought near sphere A:
- Sphere A will develop a **positive charge**.
- Sphere B will develop a **negative charge**.

**Hint:** Summarize the effects of the induction process on both spheres.

### Conclusion
When a negatively charged ebonite rod is brought near sphere A, sphere A develops a positive charge, and sphere B develops a negative charge.

### Final Answer
- Sphere A: Positive charge
- Sphere B: Negative charge