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A circular loop of diameter d is rotated...

A circular loop of diameter `d` is rotated in a uniform electric field until the position of maximum electric flux is found. The flux in this position is measured to be `phi` .What is the electric field strength?

A

`(4 phi)/(pi d^(2))`

B

`(2 phi)/(pi d ^(2))`

C

`(phi)/(pi d^(2))`

D

`(pi phi d^(2))/(4)`

Text Solution

Verified by Experts

The correct Answer is:
A

`phi = EA . Cos 0^(@) = E xx (pi d^(2))/( 4)" " :. E = (4 phi)/( pi d^(2))` .
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