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An aqueous solution contains 0.10 M H(2)...

An aqueous solution contains `0.10 M H_(2)S` and 0.20 M HCl. If the equilibrium constants for the formation of `HS^(–)` from `H_(2)S` is `1.0xx10^(–7)` and that of `S^(2-)` from `HS^(–)` ions is `1.2xx10^(–13)` then the concentration of `S^(2-)` ions in aqueous solution is

A

`5xx10^(-8)`

B

`3xx10^(-20)`

C

`6xx10^(-21)`

D

`5xx10^(-19)`

Text Solution

Verified by Experts

The correct Answer is:
B

In presence of external `H^(+)`,
`H_(2)ShArr2H^(+)+S^(2-),K_(a_(1)).K_(a_(2))=K_(eq)`
`:.([H^(+)]^(2)[S^(2-)])/([H]_(2)S)=1xx10^(-7)xx1.2xx10^(-13)`
`([0.2]^(2)[S^(2-)])/([0.1])=1.2xx10^(-20),[S^(2-)]=3xx10^(-20)`
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