The equilibrium constant at `298K` for a reaction, `A+BhArrC+D` is 100. If the initial concentrations of all the four species were 1M each, then equilibirum concentration of `D` (in mol`L^(-1)`) will be

Options

A. 1.818
B. 1.182
C. 0.182
D. 0.818

Answer

A

Explanation

Given,
`A+BhArrC+D`
No. of moles initially 1,1,1,1
At equilibrium 1-a, 1-a, 1+a ,1+a
`K_(c)=((1+a)/(1-a))^(2)=100,(1+a)/(1-a)=10`
On solving, a=0.81
`[D]_(Ateq)=1+a=1+0.81=1.81`