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The decomposition of N(2)O(4) to NO(2) i...

The decomposition of `N_(2)O_(4)` to `NO_(2)` is carried out at `280^(@)C` in chloroform. When equilibrium is reached, `0.2` mol of `N_(2)O_(4)` and `2xx10^(-3)` mol of `NO_(2)` are present in a `2L` solution. The equilibrium constant for the reaction
`N_(2)O_(4) hArr 2NO_(2)` is

A

`1xx10^(-2)`

B

`2xx10^(-3)`

C

`1xx10^(-5)`

D

`2xx10^(-5)`

Text Solution

Verified by Experts

The correct Answer is:
C
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DISHA PUBLICATION-EQUILIBRIUM-Exercise-1: Concept Builder (Topicwise) (TOPIC 1: Law of Mass Action, Equilibrium Constant (Kc and Kp) and its Applications)
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  4. At a given temperature the equilibrium constant for the reaction of ...

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  5. Which of the following is correct for the reaction? N(2)(g)+3H(2)(g)...

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  6. K(1) and K(2) are equilibrium constants for reaction (i) and (ii) N(...

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  7. 5 mole of NH(4)HS(s) start to decompose at a particular temperature in...

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  9. If the K(p) for the equilibrium, M.5H(2)O(s)hArrM.3H(2)O(s)+2H(2)O(g...

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  10. For the reaction 2NO(2)(g) hArr 2NO(g)+O(2)(g) K(c)=1.8xx10^(-6) at ...

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  11. For the reversible reaction N(2)(g)+3H(2)(g)hAr2NH(3)(g) at 500^(@...

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  12. The partial pressure of CH(3)OH((g)), CO((g)) and H(2(g)) in equilibri...

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