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For the reaction H(2)(g) + I(2)(g)hArr2H...

For the reaction `H_(2)(g) + I_(2)(g)hArr2HI(g)` at 721 K the value of equilibrium constant `(K_(c))` is 50. When the equilibrium concentration of both is `0.5` M, the value of `K_(p)` under the same condtions will be

A

0.02

B

`0.2`

C

50

D

50 RT

Text Solution

Verified by Experts

The correct Answer is:
C
`H_(2)(g)+I_(2)(g)hArr2HI(g)`
`K_(p)=K_(c)(RT)^(Deltan),Deltan=2-2=0,:.K_(p)=K_(c)`
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