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For the reaction XCO(3)hArrXO(s)+CO(2)(g...

For the reaction `XCO_(3)hArrXO(s)+CO_(2)(g), K_(p)=1.642 atm" "at727^(@)C " If 4 moles of" XCo_(3)(s)` was put into a 50 litre container and heated to `727^(@)C`
What mole percent of the `XCO_(3)` remains unreacted at equilibrium ?

A

20

B

25

C

50

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
D
Moles of `CO_(2)` present at equilibrium
`=(1.642xx50)/(0.0821xx1000)=1`
Mole % of `XCO_(3)` decomposed
`=(1)/(4)xx100=25%`
Hence, 75% remains undecomposed.
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