Home
Class 12
CHEMISTRY
What will be the H^(+) concentration in ...

What will be the `H^(+)` concentration in a solution prepared by mixing 50.0 ml of 0.20 m NaCl, 25 ml of 0.10 M NaOH and 25.0 ml of 0.30 M HCl?

A

0.5 M

B

0.05 M

C

0.02 M

D

0.10 M

Text Solution

Verified by Experts

The correct Answer is:
B

`[H^(+)]=((25xx0.3-25xx0.1))/(100)meq=0.05M`
Promotional Banner

Topper's Solved these Questions

  • EQUILIBRIUM

    DISHA PUBLICATION|Exercise Exercise-1: Concept Builder (Topicwise) TOPIC 4: Ionization of Weak Acids and Bases and Relation between Ka and Kb )|7 Videos
  • EQUILIBRIUM

    DISHA PUBLICATION|Exercise Exercise-1: Concept Builder (Topicwise) TOPIC 5: Common lon Effect, Salt Hydrolysis, Buffer Solutions and Solubility Product)|17 Videos
  • EQUILIBRIUM

    DISHA PUBLICATION|Exercise Exercise-1: Concept Builder (Topicwise) (TOPIC 2: Relation between K, Q, G and Factors Effecting Equilibrium)|9 Videos
  • ENVIRONMENTAL CHEMISTRY

    DISHA PUBLICATION|Exercise Exercise -2 : Concept Applicator|15 Videos
  • GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS

    DISHA PUBLICATION|Exercise EXERCISE -1: CONCEPT APPLICATOR|35 Videos

Similar Questions

Explore conceptually related problems

What is the [OH^(-)] in the final solution prepared by mixing 20.0 mL of 0.050 M HCl with 30.0 mL of 0.10 M Ba(OH)_(2) ?

What is the [OH]^(-) in the final solution prepared by mixing 20.0mL of 0.050M HCl with 30.0 mL of 0.10 M Ba (OH)_(2) ?

The pH of a solution obtaine by mixing 50 mL of 0.4 N HCl and 50 mL of 0.2 N NaOH is

What is the concentration of H^(+) in a solution that is prepared by mixing 50.0 mL of 0.50 M HCl with 200.0 mL of 0.25 M HCl ? Fill your Answer of the multiplying it with 10.