1 M `NH_(4)OH and 1 M HCl` are mixed to make a total volume of 300 mL. If pH of the mixture is 9.26 and `pK_(A)(NH_(4)^(+))=9.26` then what would be the volume ratio of `NH_(4)OH and HCl`

Options

A. 225 mL, 75 mL
B. 200 mL, 100 mL
C. 100mL., 200 mL
D. 150mL, 150 mL

Answer

C

Explanation

Let volume of HCl required be V mL the volume of `NH_(3)=300-VmL`
`pH=pK_(a)+log""(["salt"])/(["base"])`
`9.26=9.26-log""(V)/((300-V)-V),V=100mL`.