The precipitate of `Ag_(2)CrO_(4)(K_("sp") = 1.9 xx 10^(-12))` is obtained when equal volumes of the following are mixed.

Options

A. `10^(-5)MAg^(+)and10^(-3)MCrO_(4)^(2-)`
B. `10^(-5)MAg^(+)and10^(-2)MCrO_(4)^(2-)`
C. `10^(-4)MAg^(+)and10^(-2)MCrO_(4)^(2-)`
D. `10^(-7)MAg^(+)and10^(-3)MCrO_(4)^(2-)`

Answer

C

Explanation

`Ag_(2)CrO_(4)hArr2Ag^(+)+CrO_(4)^(2-)`
`K_(ip)=[Ag^(+)]^(2)[CrO_(4)^(2-)]` and for precipitation `K_(sp)ltK_(ip),:.` Equal volumes of `Ag^(+)` and `CrO_(4)^(2-)` are used, so all the concentration terms must be divided by 2.
Among the given options, only option (b) `K_(ip)` execcds the `K_(sp)` value of `Ag_(2)CrO_(4)` and hence precipitation occure.