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When sulphur ( in the form of S(B)) is h...

When sulphur ( in the form of `S_(B))` is heated at temperature `T`, at equilibrium , the pressure of `S_(B)` falls by `30%` from `1.0 atm`, because `S_(B)(g)` in partially converted into `S_(2)(g)`.
Find the value of `K_(P)` for this reaction.

A

2.96

B

6.14

C

204.8

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A
`K_(P)=(P_(S_(2)(g))^(4))/(P_(S_(2)(g)))=((4xx0.3^(4)))/(0.70)=2.96`
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