Phosphorus pentachloride dissociates as follows in a closed reaction vessel.
`PCl_5(g) hArr PCl_3(g) +Cl_2(g)`
If total pressure at equilibrium of the reactions mixture is P and degree of dissociation of `PCl_5`is x, the partial pressure of `PCl_3` will be:

Options

A. `((x)/(x-1))P`
B. `((x)/(1-x))P`
C. `((x)/(1+x))P`
D. `((2x)/(1-x))P`

Answer

C

Explanation

`underset(1-x)(PCl_(5)(g))hArrunderset(x)(PCl_(3)(g))+underset(x)(Cl_(2)(g))`
Total moles after dissociation
`1-x+x+x=1+x`
`P_(PCl_(3))` = mole fraction of `PCl_(3)xx` Total pressure `=((x)/(1+x))P`