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For the reaction H(2)(g)+CO(g)hArrCO(g)...

For the reaction
`H_(2)(g)+CO(g)hArrCO(g)+H_(2)O(g),` if the initial concentration of`[H_(2)]=[CO_(2)]`and x moles /litres of hydrogen is consummed at equilibrium , the correct expression of `K_(p)` is :

A

`(x^(2))/((1-x^(2)))`

B

`((1+x^(2)))/((1-x^(2)))`

C

`(x^(2))/((2+x^(2)))`

D

`(x^(2))/((2-x^(2)))`

Text Solution

Verified by Experts

The correct Answer is:
A
`H_(2)O(g)+CO_(2)(g)hArrCO(g)+H_(2)O(g)`
`t=0" "1M" "1M`
`t=t_(eq)" "(1-x)" "(1-x)" "(x)" "(x)`
`:.Deltan_(g)=0`
`impliesK_(p)=K_(c)=(x^(2))/((1-x^(2)))`
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