A sample of 16 g charcoal was brought into contact with `CH_(4)` gas contained in a vessel of 1 litre at `27^(@) C` . The pressure of gas was found to fall from 760 to 608 torr. The density of chacoal sample is `1.6 g//m^(3)` . What is the volume of the `CH_(4)` gas adsorbed per gram of the adsorbent at 608 torr and `27^(@)C`?

Options

A. `125 m^(2)g^(-1)`
B. `3.48m^(2)g^(-1)`
C. `16.25 m^(2)//g^(-1)`
D. None of these

Answer

B

Explanation

Final volume of gas, at 608 torr pressure
`V_(2)=(p_(1)V_(1))/(P^(2))=(760xx1)/(608)`
`=-1.25LorV_(2)=1250mL`
Volume occupied by= gas Volume of vessel - Volume occupied by charcoal
`=1000-(16)/(1.6)=990 mL`
Difference of volume is due to adsorption of gas by charcoal.
`:.`Volume of gas adsorbed by charcoal=1250-990 Volume of the gas adsorbed per gram of charcoal`= (260)/(16)=16.25 mL//g` at 608 torr and `27^(@)C`