`(CH_(3))_(2)C=CHCOCH_(3)` can be oxidised to `(CH_(3))_(2) C=CHCOOH` by

Options

A. Chromic acid
B. `NaOI`
C. `Cu" at "300^(@)C`
D. `KMnO_(4)`

Answer

B

Explanation

Chromic acid and `KMnO_(4)` will cleave the molecules at the site of double bond while Cu at `300^(@)C` cannot oxidise `COCH_(3)` to `COOH`. The only reagent suitable for thic conversion is `NaOH` or `NaOH+I_(2)` (iodoform test):
`(CH_(3))_(2)C=CHCOCH_(3) overset(NaOH)rarr (CH_(3))_(2)C=CHCOOH+CHI_(3)`.