Identify Z in the following sequence of reactions -
`CH_(3)COONH_(4) overset(Delta)rarr X overset(P_(2)O_(5))rarr Y overset(H_(2)O//H)rarr Z`

Options

A. `CH_(3)-CH_(2)-CO-NH_(2)`
B. `CH_(3)-CN`
C. `(CH_(3)CO)_(2)`
D. `CH_(3)-COOH`

Explanation

To identify Z in the given sequence of reactions, let's break down the steps involved:

1. **Starting Material**: The initial compound is ammonium acetate, represented as CH₃COONH₄.

2. **Heating the Ammonium Acetate**: When ammonium acetate is heated (Δ), it undergoes a decomposition reaction. During this process, a water molecule (H₂O) is eliminated. The reaction can be represented as:
\[ CH₃COONH₄ \xrightarrow{\Delta} CH₃C(=O) + NH₃ \]
Here, we are left with acetic acid (CH₃C(=O)OH) and ammonia (NH₃). However, for the purpose of this reaction, we focus on the acetic acid.

3. **Reaction with P₂O₅**: The next step involves the use of phosphorus pentoxide (P₂O₅), which is a dehydrating agent. When acetic acid is treated with P₂O₅, it loses a water molecule to form an anhydride:
\[ CH₃C(=O)OH \xrightarrow{P₂O₅} CH₃C(=O)O + H₂O \]
This results in the formation of acetic anhydride (CH₃C(=O)).

4. **Hydrolysis of Acetic Anhydride**: The final step involves the hydrolysis of acetic anhydride in the presence of water (H₂O). The hydrolysis of acetic anhydride yields acetic acid:
\[ CH₃C(=O)O + H₂O \rightarrow 2 CH₃C(=O)OH \]
Thus, the product Z after hydrolysis is acetic acid (CH₃COOH).

### Final Answer:
Z is acetic acid (CH₃COOH).