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A man had 100 kgs of sugar, part of whic...

A man had 100 kgs of sugar, part of which he sold at 7% profit and rest at 17% profit. He gained 10% on the whole. How much did he sell at 7% profit?

A

65 kg

B

35 kg

C

30 kg

D

70 kg

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we can use the method of allegation to find out how much sugar was sold at 7% profit. ### Step 1: Understand the given information - Total sugar = 100 kg - Profit on part sold at 7% = 7% - Profit on part sold at 17% = 17% - Overall profit = 10% ### Step 2: Set up the allegation We will set up an allegation to find the ratio of the quantities sold at different profit percentages. - Profit percentages: - Lower profit (7%) = 7% - Overall profit = 10% - Higher profit (17%) = 17% ### Step 3: Calculate the differences Using the allegation method: - Difference between higher profit and overall profit: \( 17\% - 10\% = 7\% \) - Difference between overall profit and lower profit: \( 10\% - 7\% = 3\% \) ### Step 4: Set up the ratio Now we can set up the ratio of the quantities sold at different profits: - The ratio of quantities sold at 7% profit to those sold at 17% profit is: - 3 (for 17%) : 7 (for 7%) This means for every 3 parts sold at 17% profit, 7 parts are sold at 7% profit. ### Step 5: Calculate the total parts Total parts = 3 + 7 = 10 parts. ### Step 6: Calculate the quantity sold at 7% profit Now, we can find out how much sugar was sold at 7% profit: - Quantity sold at 7% profit = (7 parts / 10 parts) × 100 kg - Quantity sold at 7% profit = \( \frac{7}{10} \times 100 = 70 \) kg ### Conclusion Thus, the man sold **70 kg** of sugar at 7% profit.
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