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ABCD is a cyclic quadrilateral whose ver...

ABCD is a cyclic quadrilateral whose vertices are equidistant from the point O (centre of the circle). If `angleCOD = 120^@ ` and `angleBAC = 30^@`, then the measure of `angleBCD` is

A

`180^@ `

B

`150 ^@`

C

`60^@`

D

`90^@`

Text Solution

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The correct Answer is:
To solve the problem, we need to find the measure of angle BCD in the cyclic quadrilateral ABCD, given that angle COD = 120° and angle BAC = 30°. ### Step-by-Step Solution: 1. **Understanding the Cyclic Quadrilateral**: - A cyclic quadrilateral is a quadrilateral whose vertices lie on the circumference of a circle. The opposite angles of a cyclic quadrilateral sum up to 180°. 2. **Identify the Angles**: - We are given: - Angle COD = 120° - Angle BAC = 30° - We need to find angle BCD. 3. **Using the Central Angle Theorem**: - The angle at the center (angle COD) is twice the angle at the circumference (angle BCD) that subtends the same arc. - Therefore, if angle COD = 120°, then angle BCD = ½ * angle COD. - So, angle BCD = ½ * 120° = 60°. 4. **Finding Angle DAB**: - Now, we also know that angle BAC = 30°. - Since angle DAB is subtended by the same arc as angle BCD, we can find angle DAB using the relationship between angles in a cyclic quadrilateral. - Angle DAB = angle BAC + angle BCD = 30° + 60° = 90°. 5. **Using the Property of Cyclic Quadrilaterals**: - The sum of opposite angles in a cyclic quadrilateral is 180°. - Therefore, angle A + angle C = 180°. - Here, angle A (DAB) = 90°, so angle C (BCD) = 180° - 90° = 90°. 6. **Conclusion**: - Thus, the measure of angle BCD is 90°. ### Final Answer: Angle BCD = 90°. ---
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