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Gautam goes to office at a speed of 12 k...

Gautam goes to office at a speed of 12 kmph and returns home at 10 kmph. His average speed is :

A

11 kmph

B

22 kmph

C

10.9 kmph

D

12.5 kmph

Text Solution

AI Generated Solution

The correct Answer is:
To find Gautam's average speed for his round trip to the office, we can use the formula for average speed when the distances are the same but the speeds are different. ### Step-by-step Solution: 1. **Define the Distance**: Let the distance from Gautam's home to his office be \( D \) kilometers. 2. **Calculate Total Distance**: Since Gautam travels to the office and returns home, the total distance traveled is: \[ \text{Total Distance} = D + D = 2D \text{ kilometers} \] 3. **Calculate Time Taken for Each Leg of the Journey**: - Time taken to go to the office: \[ \text{Time}_{\text{to office}} = \frac{D}{12} \text{ hours} \] - Time taken to return home: \[ \text{Time}_{\text{return home}} = \frac{D}{10} \text{ hours} \] 4. **Calculate Total Time**: The total time taken for the round trip is: \[ \text{Total Time} = \text{Time}_{\text{to office}} + \text{Time}_{\text{return home}} = \frac{D}{12} + \frac{D}{10} \] To add these fractions, find a common denominator (which is 60): \[ \text{Total Time} = \frac{5D}{60} + \frac{6D}{60} = \frac{11D}{60} \text{ hours} \] 5. **Calculate Average Speed**: The average speed is given by the formula: \[ \text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}} = \frac{2D}{\frac{11D}{60}} = 2D \times \frac{60}{11D} \] Simplifying this gives: \[ \text{Average Speed} = \frac{120}{11} \text{ kmph} \] Calculating this gives approximately: \[ \text{Average Speed} \approx 10.91 \text{ kmph} \] ### Final Answer: Gautam's average speed is approximately **10.91 kmph**.
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