[" 24.Find the equivalent resistance across "AB],[(a)1Omega],[(b)2Omega],[(c)3Omega],[(d)4Omega]

Given the resistances of 1Omega ,2Omega ,3Omega , how will be combine them to get an equivalent resistance of (i) (11//3)Omega (ii) (11//5)Omega , (iii) 6Omega , (iv) (6//11)Omega ?

[" For what value of "R" in circuit,"],[" current through "4Omega" resistance "],[" is zero."],[[" (A) "0.5Omega,],[" (B) "1Omega,],[" (C) "5Omega]],[" (D) "4Omega]

Nine wires each of resistance r=5Omega are connected to make a prism as shown in the figure.Find the equivalent resistance of the arrangement across AB(in Omega )

A newtwork of conductors is in the form of a triangle ABC in which AB = 1Omega , BC= 2Omega and CA = 3Omega and the angular points A, B and C are joined to any point O inside the triangle by resistance 1Omega , 2Omega and 3Omega , respectively. Find the equivalent resistance between A and B. [Hing: Assume current at the entrance and exit points].

In a typical wheatstone network the resistance in cyclic order are A= 10Omega,B=5Omega,C=4Omega and D=4Omega for the bridge to be balanced.

Find the equivalent resistance when the following are connected in parallel: 1 Omega and 100 Omega and 1000 Omega