[" 21.An organic compound on analysis gave the following percentage composition."C=57.8%H=3.6%],[" & the rest is oxvaen.The molecular mass is "166" .Find its molecular formula & empirical formula.(5"]

An organic compound on analysis gave the following composition : C = 57.8% H = 3.6% and rest is oxygen. Its empirical formula is :

An organic compound on analysis gave the following percentage composition of C= 57.8, H= 3.6 and the rest is oxygen. Vapour density of the compound is 83. Find out the molecular formula of the compound.

A compound on analysis gave the following percentage composition by mass: H = 9.09, O = 36.36, C = 54.55. Molecular mass of compound is 88. Find its molecular formula.

An organic compound on analysis gave the following percentage composition : C = 57.8%, H = 3.6% and the rest is oxygen. The vapour density of the compound was found to be 83. Find out the molecular formula of the compound

An organic compound on analysis gave the following data : C = 57.82%, H=3.6%, and 38.58% is oxygen. Find its empirical formula.

A compound on analysis gave the following percentage composition C = 54.54%, H, 9.09% 0 = 36.36. The vapour density of the compound was found to be 44. Find out the molecular formula of the compound.

A compound on analysis gave the following percentage composition C = 54.54%, H, 9.09% 0 = 36.36. The vapour density of the compound was found to be 44. Find out the molecular formula of the compound.

A compound on analysis gave the following percentage composition C = 54.54%, H, 9.09% 0 = 36.36. The vapour density of the compound was found to be 44. Find out the molecular formula of the compound.

A compound on analysis gave the following percentage composition C = 54.54%, H, 9.09% 0 = 36.36. The vapour density of the compound was found to be 44. Find out the molecular formula of the compound.