O is the circumcentre of the `Delta ABC`. A and BC lie on the opposite of the centre O. If `angle BOC=120^(@)`, then `angleBAC`=

O is the circumcentre of a triangle DeltaABC .The point A and the chord BC are on the opposite side of O.If algle BOC=150^(@) .Then the angle angleBAC n is:

O is the circumcentre of Delta ABC and OD is perpendicular on the side BC, prove that angle BOD= angle BAC

Let O be the orthocentre of the triangle ABC. If angleBOC = 150^@ , Then angleBAC is

(i) The circumcentre of the triangle ABC is O, If angle BOC=80^@, then angle BAC=

In the isosceles Delta ABC,AB=AC . The circumcentre of Delta ABC is the centre O lies on the opposite side of BC in which a lies. If Delta BOC=100^(@) , then find the value of angle ABC angle ABO .

O is the circumcentre of the triangle ABC and D is the mid-point of the base BC. Prove that angleBOD = angleA

(ii) Orthocentre of the triangle ABC is O, If angle BAC=40^@ , then angle BOC=

O is the circumcentre of Delta ABC and OD bot BC . Prove that angle BOD= angle BAC