In the figure all the circles have radius 'a' and their centres form the vertices of a regular hexagon. Prove that the area enclosed between the circles is nearly equal to `24/25a^2`.

The area enclosed by the circle x^(2) + y^(2)= 2 is equal to

Find the area enclosed by the circle : x^2 + y^2 = 25 .

Find the angles formed at the centre of the circle by sides of a regular circular hexagon.

Find the area enclosed by the circle x^(2)+y^(2)=25

Find the difference between the area of a regular hexagon whose sides is 72cm and the area of the circle inscribed in it.

If three circles of radius a each are drawn such that each touches the other two, prove that the area included between them is equal to 4/25a^(2) . [Take sqrt(3)=1.73 and pi=3.14 ]

Find the area enclosed between the circle x^2+y^2=25 and the straight line x+y=5 .

Find the area enclosed between the circle x^2+y^2=25 and the straight line x+y=5 .

Six equal circles, each of radius a are placed so that each tuches other circle,s their centres are joined to form a hexagon. Prove that areas which the circles enclose is 2a^2(3sqrt(3)-pi)

In the adjoining figure, 7 congruent circles are placed in such a way that one circle is at the centre and other 6 circles ara tangent to it. A regular hexagon is drawn such that its vertices are the centres of the 6 circles, as shown here. If the area fo circle is 1 sq. cm, what is the area of rhe hexagon?