The image of `y^2=4x` in its tangent at the point (1, 2)

Tangents are drawn to the parabola y^2=4x at the point P which is the upper end of latusrectum . Image of the parabola y^2=4x in the tangent line at the point P is

The mirror image of the parabola y^2=4x in the tangent to the parabola at the point (1, 2) is (a) (x-1)^2=4(y+1) (b) (x+1)^2=4(y+1) (c) (x+1)^2=4(y-1) (d) (x-1)^2=4(y-1)

The mirror image of the parabola y^2= 4x in the tangent to the parabola at the point (1, 2) is:

The mirror image of the parabola y^2= 4x in the tangent to the parabola at the point (1, 2) is:

The mirror image of the parabola y^(2)=4x in the tangent to the parabola at the point (1,2) is:

The mirror image of the parabola y^(2)=4x in the tangent to the parabola at the point (1,2) is (a)(x-1)^(2)=4(y+1)(b)(x+1)^(2)=4(y+1)(c)(x+1)^(2)=4(y-1) (d) (x-1)^(2)=4(y-1)

If the straight line y=my+1 be the tangent of the parabola y^2=4x at the point (1,2), then the value of m will be

If the straight line y=mx+1 be the tangent of the parabola y^(2)=4x at the point (1,2) then the value of m will be-

The lngth of the tangent from the point (1, 1) to the circle x^2 + y^2 + 4x + 6y + 1 = 0 is