A small block is connected to one of two identical massless strings of lengtth `16(2)/(3) cm` each with their ends fixed to a verticle rod If the ratio of tensions `T_(1)//T_(2)` is 4 : 1 ,then what will be the angular velocity of the block ? Take `g = 9.8ms^(-2)`

A small block is connected to one end of a massless spring of un - stretched length 4.9 m . The other end of the spring (see the figure) is fixed. The system lies on a horizontal frictionless surface. The block is stretched by 0.2 m and released from rest at t = 0 . It then executes simple harmonic motion with angular frequency (omega) = (pi//3) rad//s . Simultaneously at t = 0 , a small pebble is projected with speed (v) from point (P) at an angle of 45^@ as shown in the figure. Point (P) is at a horizontal distance of 10 m from O . If the pebble hits the block at t = 1 s , the value of (v) is (take g = 10 m//s^2) . .

A small block is connected to one end of a massless spring of un-stretched length 4.9 m. The other end of the spring (see the figure) is fixed. The system lies on a horizontal frictionless surface. The block is stretched by 0.2 m and released from rest at t = 0. It then executes simple harmonic motion with angular frequency omega = (pi)/(3) rad/s . Simultaneously at t = 0, a small pebble is projected with speed nu from point P at an angle of 45^(@) as shown in the figure. Point P is at a horizontal distance of 10 m from O. If the pebble hits the block at t = 1s, the value of nu is (take g = 10 m/ s^(2) )

A small block is connected to one end of a massless spring of un-stretched length 4.9 m. The other end of the spring (see the figure) is fixed. The system lies on a horizontal frictionless surface. The block is stretched by 0.2 m and released from rest at t = 0. It then executes simple harmonic motion with angular frequency omega = (pi)/(3) rad/s . Simultaneously at t = 0, a small pebble is projected with speed nu from point P at an angle of 45^(@) as shown in the figure. Point P is at a horizontal distance of 10 m from O. If the pebble hits the block at t = 1s, the value of nu is (take g = 10 m/ s^(2) )

A uniform rod of mass m and length L is suspended with two massless strings as shown in figure. If the rod is at rest in a horizontal position the ratio of tension in the two strings T_(1)//T_(2) is

If pulley and all strings as shown are massless, then tension T_(2) = 100 N . Calculate weight of the block ( g = 10 m//s^(2))

Two particles each of mass m are moving in horizontal circle with same angular speed. If both string are of same length then the ratio of tension in string (T_(1))/(T_(2)) is

Two particles each of mass m are moving in horizontal circle with same angular speed. If both string are of same length then the ratio of tension in string (T_(1))/(T_(2)) is

In Fig. find the acceleration a of the system and the tesnions T_(1) and T_(2) in the strings. Assume that the table and the pulleys are frictionless and the strings are massless. Take g = 9.8ms^(2)

A block of mass 10 kg is suspended with two strings as shown in the fig. Find the tensions T_(1) and T_(2) in the two string.

A uniform rod of mass m and length L is suspended with two massless strings as shown in the figure. If the rod is at rest in a horizontal position the ratio of tension in the two strings T_1/T_2 is: