If the line `(x-4)/(1)=(y-2)/(1)=(z-k)/(2)` lies exactly on the plane `2x-4y+z=7`, the value of k is

The line (x-4)/1=(y-2)/1=(z-k)/2 lies exactly on the plane 2x-4y+z=7 , then the value of k is :

The line (x-4)/1=(y-2)/1=(z-k)/2 lies exactly on the plane 2x-4y+z=7 then the value of k is (A) 7 (B) -7 (C) 1 (D) none of these

The line (x-4)/(1) =(2y-4)/(2)=(k-z)/(-2) lies exaclty in the plane 2x-4y+z=7 find the value of k

If the line (x-4)/(1)=(y-2)/(1)=(z-q)/(p) lies completely in the plane 2x-4y+z=7 , then the ordered pair (p, q) is

If the line (x-4)/(1)=(y-2)/(1)=(z-q)/(p) lies completely in the plane 2x-4y+z=7 , then the ordered pair (p, q) is

If the line (x-4)/(1) = (y-2)/(1) = (z+k)/(2) lies in the plane 2x -4y + z =7 then k =........

The line (x-3)/(1)=(y-2)/(2)=(z-k)/(2) lies completely in the plane 2x-2y+z=0 for k equals