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If secxcos5x+1=0,w h e r e0<xlt=pi/2 , f...

If `secxcos5x+1=0,w h e r e0

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If secxcos5x+1=0 , where 0ltxle(pi)/(2) , then find the value of x.

If secxcos5x+1=0 , where 0ltxle(pi)/(2) , then find the value of x.

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The number of solutions of secxcos5x+1=0 in the interval [0,2pi] is

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