A solid is hemispherical at the bottom and conical above. If the surface areas of the two parts are equal, then the ratio of its radius and the height of its conical part is `1\ :3` (b) `1\ :sqrt(3)` (c) `1\ :1` (d) `sqrt(3)\ :1`

A solid is hemispherical at the bottom and conical above. If the surface areas of the two parts are equal, then the ratio of its radius and the height of its conical part is (a) 1\ :3 (b) 1\ :sqrt(3) (c) 1\ :1 (d) sqrt(3)\ :1

A solid is hemispherical at the bottom and conical (of same radius) above it . If the surface areas of the two parts are equal then the ratio of its radius and the slant height of the conical part is

A solid is hemispherical at the bottom and conical above. If the surface areas of the two parts are equal, then the ratio of radius and height of its conical part is एक ठोस तल पर अर्द्ध गोलाकार है और ऊपर शंक्वाकार। यदि दोनों भागों के पृष्ठ क्षेत्रफल बराबर है, जो उसके शंक्वाकार भाग की त्रिज्या और ऊँचाई का अनुपात है-

A solid is in the shape of a cone mounted on a hemisphere of same base readius. If the curved surface areas of the hemisphere part and the conical part are equal then find the ratio of the radius and the height of the conical part.

The lower and upper part of a solid object are hemispherical and conical respectively. If the area of total surface of 2 parts are equal, then find the ratio of the height of two parts of this object.

The shape of the lower part of a solid object is like a hemisphere and the upper part like a right circular cone . If the surface area of the two parts be equal , then find the ratio of the length of radius and height of the cone .

A hemisphere and a cone have equal bases. If their heights are also equal, then the ratio of their curved surfaces will be (a) 1 : 2 (b) 2 : 1 (c) 1\ :sqrt(2) (d) sqrt(2)\ :1

The area of a square is equal to the area of a circle.The ratio between the side of the square and the radius of the circle is (a) sqrt(pi):1 (b) 1:sqrt(pi)(c)1:pi(d)pi:1

The area of a square is equal to the area of a circle. The ratio between the side of the square and the radius of the circle is (a) sqrt(pi):1 (b) 1:sqrt(pi) (c) 1:pi (d) pi:1

A water tank open at the top is hemispherical at the bottom and cylindrical above it.If radius of the hemisphere is 12m and the total capacity of the tank is 3312 pi backslash m^(3), then the ratio of the surface areas of the hemispherical and the cylindrical portions is (a) 1:1 (b) 3:5 (c) 4:5 (d) 6:5