using the illustration when both surfaces 1 and 2 are exposed to the atmoshere, `P_1` and `P_2` are gauge pressure , and `h_1` and `h_2` are heights .

The Bernoulli equation for this situation is `h_1+P_1 /W+V_1^2/"2a"=h_2+P_2/W+V_2^2/"2a"`
The velocity of the fluid leavening point (2) is constant and can be expressed as

using the illustration when both surfaces 1 and 2 are exposed to the atmoshere, P_1 and P_2 are gauge pressure , and h_1 and h_2 are heights . The Bernoulli equation for this situation is h_1+P_1 /W+V_1^2/"2a"=h_2+P_2/W+V_2^2/"2a" The value of P_1 and P_2 are such that

using the illustration when both surfaces 1 and 2 are exposed to the atmoshere, P_1 and P_2 are gauge pressure , and h_1 and h_2 are heights . The Bernoulli equation for this situation is h_1+P_1 /W+V_1^2/"2a"=h_2+P_2/W+V_2^2/"2a" The value of P_1 and P_2 are such that

using the illustration when both surfaces 1 and 2 are exposed to the atmoshere, P_1 and P_2 are gauge pressure , and h_1 and h_2 are heights . The Bernoulli equation for this situation is h_1+P_1 /W+V_1^2/"2a"=h_2+P_2/W+V_2^2/"2a" If an Identical outlet were placed at exactly the same point on the left side of the container, the velocity would be

using the illustration when both surfaces 1 and 2 are exposed to the atmoshere, P_1 and P_2 are gauge pressure , and h_1 and h_2 are heights . The Bernoulli equation for this situation is h_1+P_1 /W+V_1^2/"2a"=h_2+P_2/W+V_2^2/"2a" If an Identical outlet were placed at exactly the same point on the left side of the container, the velocity would be

The top surface of an incompressible liquid is open to the atmosphere. The pressure at a depth h_(1) below the surface is p_(1) . What is the pressure p_(2) at depth h_(2) = 2h_(1) compare with p_(1) ?

Calculate the partial pressures of O_2 and H_2 in a mixture of 3 moles of O_2 and 1 mole of H_2 at S.T.P.

Calculate the partial pressures of O_2 and H_2 in a mixture of 3 moles of O_2 and 1 mole of H_2 at S.T.P.