if `m^2+1/m^2=23` evaluate `m+1/m` and `m-1/m`

m^2-m+1=0 find the value of m

If m + (1)/(m) = sqrt3 , then find the simpliest value of (i) m^(2) + (1)/(m^(2)) and (ii) m^(3) + (1)/(m^(3)) :

If x= m-2 and x/m - (x+1)/m =1 , find 'm'

Evaluate : ( m^( 1/2 ) times m^( 1/4 ) times m^( 1/4 ) )/ ( m^(1/4 ) times m^( 1/4 ) times 1/( m^(1/16 )) )

Find the nth and 6th term of the AP (2m + 1)/m , (2m-1)/m , (2m-3)/m..

If m+ (1)/(m-2)=0 , find (m-2)^(12) + (1)/((m-2)^(11))= ?

If m+ (1)/(m-2)=4 , find (m-2)^(111) + (1)/((m-2)^(111))= ?

In figure, find the velocity of m_1 in ms^-1 when m_2 falls by 9m . Given m_1=m , m_2=2m (take g=10ms^-2 ).

In figure, find the velocity of m_1 in ms^-1 when m_2 falls by 9m . Given m_1=m , m_2=2m (take g=10ms^-2 ).