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d/(dx)[cos(1-x^2)^2]=...

`d/(dx)[cos(1-x^2)^2]=`

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d/(dx)(cos^-1((1-x^2)/(1+x^2)))=

(d)/(dx) {cos ((1-x ^(2))/(1+ x ^(2)))}=

d/dx [cos^(-1)((1-x^(2))/(1+x^(2)))] at x = -1/sqrt2 .

(d)/(dx)[log(cos h(2x))]=

The value of d/(dx) [cos^(-1)(cos x)] is

(d)/(dx)[cos^(2)(cos^(-1)sqrt((2+x)/(2-x)))] is

(d)/(dx)cos^(-1)(sin x)=

(d)/(dx)[sin^(-1){cos(x^(2)-2)}]=

(d)/(dx)[(1+cos2x+sin2x)/(1+sin2x-cos2x)]=

(d)/(dx)[cos^(-1)sqrt((1+x^(2))/(2))=