A girl is twice as old as her sister. Five years hence, the product of their ages (in years) will be 375. Find their present ages.

A girl is twice as old as her sister. Four years hence, the product of their ages (in years) will be 160. Find their present ages.

A girl is twice as old as her sister.Four years hence,the product of their ages (in years) will be 160. Find their present ages.

If 2 is added to numerator and denoinator to a fraction, it becomes 9/10 . If 3 is subtracted from numerator and denominator , the fraction becomes 4/5 . Find the fraction. OR A girl is twice as old as her sister. Four years, hence the product of their ages ( in years) will be 160. Find their present ages.

A girl is twice as old as her sister.four years hence,the product of their ages (in years) will be 160. Find their present ages?

The ratio of the ages of Arvind and Renu is 3:5. Five years hence, the ratio of their ages will be 4:5. Find their present ages.

Age of Vineetha is twice her sisters age. After 4 years the product of their ages will be '160 .' Find the present ages of both.

A woman is six times as old as her son.Two years ago,the product of their ages was 84. Find their present ages.

The sum of ages of Meenakshi and her daughter is 45 years. Five years ago, the product of their ages (in years) was 124. Determine Meenakshi and her daughter's present ages.

The present age of a man is twice that of his son. Eight years hence, their ages will be in the ratio 7:4 . Find their present ages.