The normal reaction on a body placed in a lift moving up with constant acceleration `2ms^(-1) ` is 120 N. Mass of the body is (Take `g = 10ms^(-2)`)

A boy of 50 kg is in a lift moving down with an acceleration 9.8ms^(-2) .The apparent weight of the body is (g=9.8ms^(-2))

A person of 60 kg enters a lift going up with an acceleration 2 ms^(- 2) The vertical upward force acting on the person will be (g = 10 ms ^(-2))

An object of mass 5 kg is attached to the hook of a spring balance and the balance is suspended vertically from the roof of a lift. The reading on the spring balance when the lift is going up with an acceleration of 0.25 ms^(-2) is take, (take, g=10ms^(-2) )

A block of mass 10kg is moving up on an inclined plane with constant acceleration 2 ms^(-2) by applying a constant force F as shown in the figure. (take, g = 10 ms^(-2) ). If the work done on the block by applied force F in 2s is 120x N Joule then the value of N is?

A boy whose mass is 50 kg stands on a spring balance inside a lift. The lift starts to ascent with an acceleration of 2ms^(-2) . The reading of the machine or balance (g=10ms^(-2)) is

The apparent weight of man inside a lift moving up with certain acceleration is 900N. When the lift is coming down with the same acceleration apparent weight is found to be 300N. The mass of the man is (g = 10 ms^(-2) )