It is known that a lot of 10 articles contains 3 defectives. A sample of 4 articles is drawn at random from the lot. If X be the random variable of defective articles in the sample, then the value of `P(0 lt X lt 2)` is -

From a lot of 10 items containing 3 defectives, a sample of 4 items is drawn at random without replacement. The expected number of defective items is

A lot of 20 bulbs contain 4 defective ones. One bulbs is drawn at random from the lot. What is the probability that this bulb is defective?

A lot of 20 bulbs contains 4 defective ones. One bulb is drawn at random from the lot. What is the probability that this bulb is defective?

A lot of 20 bulbs contains 4 defective ones. One bulb is drawn at random from the lot. What is the probability that the bulb is defective?

A lot of 20 bulbs contain 4 defective ones. One bulb is drawn at random from the lot. What is the probability that this bulb is defective?

A lot of 20 bulbs contain 4 defective ones. One bulb is drawn at random from the lot. What is the probability that this bulb is defective ?

A sample of 4 items is drawn at random from a lot of 10 items, containing 3 defectives. If x denosts the number of decective items I the sampe, then P(0 lt x lt 3) is equal to-

In a lot of 25 articles, 5 are defective. Four articles are drawn at random from the lot. Find the probability that exactly 2 of the drawn articles are defective.

From a lot of 10 items containing 3 defective items a sample of 4 items is drawn at random. Let the random variable 'X' denote the number of defective items in the sample. If the sample is drawn without replacement, find : (i) The Probability Distribution of X (ii) Mean of X (iii) Variance of X.

From a lot of 10 items containing 3 defective items a sample of 4 items is drawn at random. Let the random variable 'X' denote the number of defective items in the sample. If the sample is drawn without replacement, find: the probability distribution of X.