`4x+4y-5z=12, 8x+12y-13z=32` से निर्धारित सरल रेखा के समीकरण सममित रूप में लिखिए ।

4x -5y-11z=12,. x-3y+z=1 2x + 3y-7z = 2

Solve: x-y+2z=7 3x+4y-5z=-5 2x-y+3z=12

8x + y + 2z = 4x + 2y + z = 1x + y + z = 2

The equation of the line intersection of the planes 4x+4y-5z=12 and 8x+12y-13z=32 can be written as: (A) x/2=(y-1)/3=(z-2)/4 (B) x/2=y/3=(z-2)/4 (C) (x-1)/2=(y-2)/3=z/4 (D) (x-1)/2=(y-2)/(-3)=z/4

The equation of the line intersection of the planes 4x+4y-5z=12 and 8x+12y-13z=32 can be written as: (A) x/2=(y-1)/3=(z-2)/4 (B) x/2=y/3=(z-2)/4 (C) (x-1)/2=(y-2)/3=z/4 (D) (x-1)/2=(y-2)/(-3)=z/4

Find the equation of the line of intersection of the planes 4x + 4y - 5z = 12, 8x + 12y - 13z = 32 in the symmetric form.