`((5x)/(3)-(y)/(2))^(2)` का विस्तार कीजिए ।

यदि (x)/(y)=((3)/(2))^(2)div ((5)/(7))^(0) , तब ((y)/(x))^(2) का मान क्या होगा -

(y)=2-3x-5x^(2)

If x+1/x= 8 , then find the value of (5x)/(x^2+1-6x) यदि x+1/x= 8 है, तो (5x)/(x^2+1-6x) का मान ज्ञात कीजिए ।

" (8) "int(sin^(2)x-cos^(2)x)/(sin^(2)x cos^(2)x)dx" का मान ज्ञात कीजिए। "

If 3x^2-5x+1=0 , then the value of (x^2+ 1/(9x^2)) is : यदि 3x^2-5x+1=0 , तो (x^2+ 1/(9x^2)) का मान ज्ञात कीजिए ।

If 9x^2+y^2=37 and xy = 2 , x, y> 0 , then the value of (27x^3+y^3) is : यदि 9x^2+y^2=37 और xy = 2 , x, y> 0 , तो (27x^3+y^3) का मान ज्ञात कीजिए ।

Simplify : (i) (5x - 9y) - (-7x + y) (ii) (x^(2) -x) -(1)/(2)(x - 3 + 3x^(2)) (iii) [7 - 2x + 5y - (x -y)]-(5x + 3y -7) (iv) ((1)/(3)y^(2) - (4)/(7)y + 5) - ((2)/(7)y - (2)/(3)y^(2) + 2) - ((1)/(7)y - 3 + 2y^(2))

(5x + 3y) (5x-3y) (25x ^ (2) + 9y ^ (2))

Factorise 25x^(2) - 30xy + 9y^(2) . The following steps are involved in solving the above problem . Arrange them in sequential order . (A) (5x - 3y)^(2) " " [ because a^(2) - 2b + b^(2) = (a-b)^(2)] (B) (5x)^(2) - 30xy + (3y)^(2) = (5x)^(2) - 2(5x)(3y) + (3y)^(2) (C) (5x - 3y) (5x - 3y)