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At 88^(@)C benzene has a vapour pressure...

At `88^(@)C` benzene has a vapour pressure of 900 torr and toluene has a vapour pressure of 360 torr. What is the mole fraction of benzene in the mixture with toluene that will boil at `88^(@)C` at 1 atm pressure? (Consider that benzene toluene form an ideal solution):

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At 88^(@)C benzene has a vapour pressure of 900 torr and toluene has vapour pressure of 360 torr. What is the mole fraction of benzene in the mixture with toluene that will be boil at 88^(@)C at 1 atm pressure, benzene- toluene form an ideal solution.

At 88^(@)C benzene has a vapour pressure of 900 torr and toluene has vapour pressure of 360 torr. What is the mole fraction of benzene in the mixture with toluene that will be boil at 88^(@)C at 1 atm pressure, benzene- toluene form an ideal solution.

At 88^@C benzene has a vapour pressure of 900 torr and toluene has a vapour pressure of 360 torr. What is the mole fraction of benzene in the mixture with toluene that will boil at 88^@C at 1 atm pressure, benzene toluene form an ideal solution:

Benzene has vapour pressure of 70 torr and methyl benzene has 20 torr. If we have an equimolar mixture of both then find mole fraction of benzene in vapour phase?