The angle of banking `theta` for a cyclist taking a turn on a curved road of radius r, with a velocity v is given by tan `theta=(v^(n))/(rg)`. What is the value of n?

For a curved track of radius R, banked at angle theta

For a curved track of radius R, banked at angle theta

For a curved track of radius R, banked at angle theta

When a cyclist negotiates a circular path of radius .r. with velocity .v., making an angle theta with the vertical, show that tantheta=v^(2)/(rg) .

The relation tan theta = v^(2)// r g gives the angle of banking of the cyclist going round the curve . Here v is the speed of the cyclist , r is the radius of the curve , and g is the acceleration due to gravity . Which of the following statements about the relation is true ?

The relation tan theta = v^(2)// r g gives the angle of banking of the cyclist going round the curve . Here v is the speed of the cyclist , r is the radius of the curve , and g is the acceleration due to gravity . Which of the following statements about the relation is true ?

The maximum speed with which a vehicle can be safely driven along curved road of radius r, banked at angle theta is

A cyclist is moving along a curvature of radius r at a constant speed v. The angle made by the cyclist with the vertical plane is