Based on the equilibrium constant for the reaction below :
`2SO_3(g)hArr2SO_2(g)+O_2(g) " " K=1.8xx10^(-5)`
What is the equilibrium constant for the reaction
`SO_2(g)+1/2O_2(g)hArr SO_3(g) " " K=?`

The equilibrium constant for the reaction: SO_3(g) hArr SO_2(g) +1/2O_2(g) is 0.18 at 900 K. What will be the equilibrium constant for the reaction: 2SO_2(g) + O_2(g) hArr SO_3(g)

The equilibrium constant of the reaction, SO_(2)(g) + 1/2 O_(2)(g) hArr 2SO_(3)(g) is 5 xx 10^(-2)atm . The equilibrium constant of the reaction, 2SO_(3)(g) hArr 2SO_(2)(g) + O_(2)(g)

The equilibrium constant for the reaction 2SO_(3(g))hArr2SO_(2(g))+O_(2(g)) is 0.15 at 900 K. Calculate the equilibrium constant for the reaction 2SO_(2(g))+O_(2(g))hArr2SO_(3(g)) at the same temperature.

The equilibrium constant for the reaction 2SO_(3(g))hArr2SO_(2(g))+O_(2(g)) is 0.15 at 900 K. Calculate the equilibrium constant for the reaction 2SO_(2(g))+O_(2(g))hArr2SO_(3(g)) at the same temperature.

The equilibrium constant for the reaction 2SO_(3(g))hArr2SO_(2(g))+O_(2(g)) is 0.15 at 900 K. Calculate the equilibrium constant for the reaction 2SO_(2(g))+O_(2(g))hArr2SO_(3(g)) at the same temperature.

The equilibrium constant for the reaction 2SO_(3(g))hArr2SO_(2(g))+O_(2(g)) is 0.15 at 900 K. Calculate the equilibrium constant for the reaction 2SO_(2(g))+O_(2(g))hArr2SO_(3(g)) at the same temperature.

The equilibrium constant of the reaction SO_2(g)+1/2O_2(g) hArr SO_3(g) "is " 4xx10^(-3) "atm"^(-1//2) . The equilibrium constant of the reaction 2SO_3(g)hArr2SO_(2)(g)+O_(2)(g) would be :

The equilibrium constant for the reaction 2SO_(2)(g)+O_(2)(g)hArr 2SO_(3)(g) is 256 at 1000 K. The equilibrium constant for the reaction : SO_(3)(g)hArr SO_(2)(g)+1//2 O_(2)(g) is :