If `int sin^(-1) ( sqrt( (x)/(1 + x) ) )dx = A(x) tan^(-1) (sqrtx) + B(x) + C `, where C is a constant of integration then the ordered pair (A(x) , B(x) ) can be :

If int ( cos x - sin x )/( sqrt(8 - sin 2x ))dx = a sin^(-1) (( sin x + cos x )/(b)) +c , where c is a constant of integration, then the ordered pair (a, b) is equal to :

If int (2x + 5 )/(sqrt(7 - 6 x - x ^ 2 )) dx = A sqrt (7 - 6x - x ^ 2 ) + B sin ^ ( -1) (( x + 3 )/( 4 ) ) + C (Where C is a constant of integration), then the ordered pair (A, B) is equal to :

If int (2x + 5 )/(sqrt(7 - 6 x - x ^ 2 )) dx = A sqrt (7 - 6x - x ^ 2 ) + B sin ^ ( -1) (( x + 3 )/( 4 ) ) + C (Where C is a constant of integration), then the ordered pair (A, B) is equal to :

Consider int x tan^(-1) x dx = A (x^(2) + 1) tan^(-1) x + Bx + C , where C is the constant of integration What is the value of B ?

If int (x+1)/(sqrt(2x-1))dx = f(x)sqrt(2x-1)+C , where C is a constant of integration, then f(x) is equal to

If int (x+1)/(sqrt(2x-1))dx = f(x)sqrt(2x-1)+C , where C is a constant of integration, then f(x) is equal to

If int (x+1)/(sqrt(2x-1))dx = f(x)sqrt(2x-1)+C , where C is a constant of integration, then f(x) is equal to

If int (x+1)/(sqrt(2x-1))dx = f(x)sqrt(2x-1)+C , where C is a constant of integration, then f(x) is equal to