Line `L,` perpendicular to the line with equation `y = 3x – 5`, contains the point `(1, 4).` The x-intercepts of `L` is

Line L is perpendicular to the line with equation y= 3x – 5, contains the point (1,4). The x-intercept of L is

" If the line "l" - is perpendicular to the line which is passing through the points "(6,3),(-2,4)" then the slope of "l" is "

A line L is perpendicular to the line 3x-4y-7=0 and touches the circle x^(2)+y^(2)-2x-4y-4=0 , the y -intercept of the line L can be:

A straight line L is perpendicular to the line 5x-y=1. The area of the triangle formed by the line L and the cordinate axes is 5 square units.Find the equation of the line L.

A straight line L is perpendicular to the line 5x-y=1. The area of the triangle formed by line L, and the coordinate axes is 5. Find the equation of line L.

Find equation of the line perpendicular to the line x having x intercept 3.

The perpendicular from the origin to a line L meets it at the point (3, -9) , equation of the line L is

he straight line L is perpendicular to the line 4x-y=1. The area of the triangle formed by the line L and the coordinate axis is 8. Then the equation of the straight line with positive intercept on y-axis,is

If a line L is perpendicular to the line 5x-y=1 ,and the area of the triangle formed by the line L and the coordinate axes is 5 ,then the distance of line L from the line x+5y=0 is

Lying in the plane x+y+z=6 is a line L passing through (1, 2, 3) and perpendicular to the line of intersection of planes x+y+z=6 and 2x-y+z=4 , then the equation of L is