Let `f(x)=[3+2cos x],x in(-(pi)/(2),(pi)/(2))` where [.] is the GIF .Then the number of points of discontinuity of f(x) is

Let f(x)=[x+1]sin((pi)/([x+2])), where [.] denotes the greatest integer function.Points of discontinuity of f(x) in the domain are

Let f(theta)=[tan theta[cot theta]],theta in[(pi)/(12),(pi)/(2)) then the number of points where f(x) is discontinuous is (where [ .] denotes the greatest integer function)

If f(x)=(1+x)/([x]),x in[1,3] , then the number of points of discontinuity are (where [.] is G.I.F.)

[" If "],[" f(x) "=sgn(3x cos^(-1)(x)-6cos^(-1)(x)-pi x+2 pi)],[" ,then the number of points "],[" of discontinuity of "f(x)" is/are "],[" [Note: sgn k denotes signum "],[" function of k.] "]

Let f(x) = x cos^(-1)(sin-|x|) , x in (-pi/2,pi/2)

Let f(x)=[cosx+ sin x], 0 lt x lt 2pi , where [x] denotes the greatest integer less than or equal to x. The number of points of discontinuity of f(x) is

If f(x)=max{tanx, sin x, cos x} where x in [-(pi)/(2),(3pi)/(2)) then the number of points, where f(x) is non -differentiable, is

Let f(x)=[x]sin((pi)/([x+1])) where [.] greatest integer function.The domain of f is......and the points of discontinuity of fin the domain are....

Let f(x)=|x|+|sinx|, x in (-pi/ 2,3pi/2). Then , f is

Let g(x)=f(f(x)) where f(x)={1+x;0<=x<=2} and f(x)={3-x;2