A string will break under a load of 5kg .To the one end of such a 2m long string,a mass of 1kg is attached.The maximum rpm in the horizontal plane,so that the string does not break is ?(g=10m`s^(-2)` and `pi^(2)~~10`)

Find the tension in the horizontal string PQ and the string QR in the given figure. [Take g=10m//s^(2) ]

A string breaks under a load of 4 kg. A mass weighing 200 g is attached to the end of this string which is one metre long and rotation when the string breaks, Is nearly(g=10 m//s^2 )

A string breaks under a load of 4.8kg A mass of 0.5 kg is attached to one end of a string 2 m long and is rotated in a horizontal circle. Calculate the greatest number of revolutions that the mass can make without breaking the string.

A 1kg stone at the end of 1m long string is whirled in a vertical circle at a constant speed of 4m//s . The tension in the string is 6N , when the stone is at (g=10m//s^(2))

The breaking tension of a string if 50 N. A body of mass 1 kg is tied to one end of a 1m long string and whirled in a horizontal circle, The maximum speed of the body should be

A stone is attached to one end of a straing and roteted in verticle cricle .If string breaks at the position of maximum tension, will break at

A uniform rod of length 1 m and mass 2 kg is suspended. Calculate tension T (in N ) in the string at the instant when the right string snaps (g = 10 m//s^(2)) .

One end of a light rod of length 1m is attached with a string of length 1m. Other end of the rod is attached at point O such that rod can move in a vertical circle. Other end of the string is attached with a block of mass 2kg. The minimum velocity that must be given to the block in horizontal direction so that it can complete the vertical is (g=10 m//s^(2))

A 'block' of mass 10 kg is suspended with string as shown in figure. Find tension in the string. (g=10m//s^(2))