Let ABCD is a rhombus in which a sides AB and AD are given by the lines `x-y-2=0` and `6x-y+3=0` respectively. Diagonals AC & BD of rhombus ABCD intersect at point P(1,2), Equation of CD can be

The diagonals AC and BD of a rhombus intersect at (5, 6). If A (3, 2) then equation of diagonal BD is

The diagonals AC and BD of a rhombus intersect at (5,6). If A(3,2), then find the equation of diagonal BD.

ABCD is a rhombus, in which the length of the diagonals AC and BD are 6 cm and 8cm, respectively. Find the perimeter of the rhombus ABCD.

The diagonals AC and BD of a rhombus intersect at (5,6). If A-=(3,2), then find the equation of diagonal BD.

Two sides of a rhombus ABCD are parallel to the lines y=x+2 and y=7x+3 If the diagonals of the rhombus intersect at the point (1,2) and the vertex A is on the y-axis,then vertex A can be

The sides AB and AD of a parallelogram ABCD are 2x-y+1=0 and x+3y-10=0 respectively and C is the point (-1, -2) . Find the equation of the diagonals AC and BD.

The sides of a rhombus ABCD are parallel to the lines x−y+2=0 and 7x−y+3=0 , If the diagonals of the rhombus intersect at P(1,2) and the vertex A (different from the origin) is on the y-axis then the ordinate of A is:

Two sides of a rhombus ABCD are parallel to the lines y = x + 2 and y = 7x + 3. If the diagonals of the rhombus intersect at the point (1, 2) and the vertex A is on the y-axis, find the possible coordinates of A. x – y – 1 = 0 are the equations of two internal bisectors of its angles.

Construct a rhombus ABCD given that side AB=5 cm and a diagonal is 6 cm.