The angular velocity of a particle is given by `omega=1.5t-3t^(@)+2`, Find the time when its angular acceleration becomes zero.

The angular velocity of a particle is given by omega=1.5t-3t^(2)+2 , Find the time when its angular acceleration becomes zero.

The angular velocity of a particle is given by the equation omega =2t^(2)+5rads^(-1) . The instantaneous angular acceleration at t=4 s is

The angular displacement of a particle is given by theta = t^3 + 2t +1 , where t is time in seconds. Its angular acceleration at t=2s is

the angular velocity omega of a particle varies with time t as omega = 5t^2 + 25 rad/s . the angular acceleration of the particle at t=1 s is

the angular velocity omega of a particle varies with time t as omega = 5t^2 + 25 rad/s . the angular acceleration of the particle at t=1 s is

The angular displacement of a particle is given by theta =t^3 + t^2 + t +1 then,the angular acceleration of the particle at t=2 sec is ……. rad s^(-2)

The angular displacement of a particle is given by theta=t^(3)+ t^(2)+ t+1 then, its angular velocity at t = 2sec is ……….. rad s^(-1)

The angular displacement of a particle is given by theta=t^(3)+ t^(2)+ t+1 then, its angular velocity at t = 2sec is ……….. rad s^(-1)

The angular displacement of a particle is given by theta =t^3 + t^2 + t +1 then, its angular velocity at t=2 sec is …… rad s^(-1)