Find the `13^(t h)`term in the expansion of `(9x-1/(3sqrt(x)))^(18),x!=0`

Explanation

To find the 13th term in the expansion of \((9x - \frac{1}{3\sqrt{x}})^{18}\), we will use the Binomial Theorem. The Binomial Theorem states that:

\[ (a + b)^n = \sum_{r=0}^{n} \binom{n}{r} a^{n-r} b^r \]

In this case, we can identify \(a = 9x\) and \(b = -\frac{1}{3\sqrt{x}}\), and \(n = 18\).

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