In the previous problem, after some time the bus will be left behind. If the bus continues moving with the same acceleration, after what time from the beginning, the bus will overtake the cyclist ?

A bus starts moving with acceleration 2 ms^(-2) . A cyclist 96 m behind the nus starts simultaneously towards the bus at a constant speed of 20 m s^(-1) After some time the bus will be left behind. If bus continues moving with the same acceelration, after what time from the begining, the bus will overtake the cyclist ?

A man is at a distance from the bus: when the bus begins to move with a constant acceleration 'a', with what minimum velocity the man should run towards the bus so as to catch it?

A girl dropped an orange in a moving bus with acceleration a, what will be the acceleration of the apple with respect to the bus?

A man runs at a speed of 4 ms to overtake a standing bus. When he is 6m behind the door (a ) the bus moves forward and continues moving with constant acceleration of 1.2 m/s^2 . The time after which the man is able to catch the bus is :

A bus starts moving with an acceleration2 ms? A cyclist 96 m behind the bus starts simultaneously towards the bus at 20 m s-, after what time will he able to overtake the bus?