If the concentration of glucose `(C_(6)H_(12)O_(6))` in blood is 0.9 g `L^(-1)`, what will be the molarity of glucose in blood?

If the concentration of glucose (C_(6)H_(12)O_(6)) in blood is 0.72 gL^(-1) , the molarity of glucose in blood is _____ xx 10^(-3)M . (Nearest integer) [Given: Atomic mass of C=12, H=1, O=16u]

If the concentration of glucose in blood is 0.9 g*L^(-1) , then its molarity will be-

The oxidation number of C in glucose (C_(6)H_(12)O_(6)) is

Concentration of glucose in blood is:

360 amu of Glucose (C_6H_12O_6) contains :

360 amu of Glucose (C_6H_12O_6) contains :

Define the following terms, (a) Ideal solution. (b) Azeotrope. (c) Osmotic pressure. (ii) A solution of glucose (C_(6)H_(12)O_(6)) in water is labelled as 10% by weight what would be the molality of the solution ? (Molar mass of glucose=180 g mol^(-1) )

If concentration of glucose in blood is 0.72 gL^(-1) . The molarity of glucose is:

(a) Define the following terms : (i) Ideal solution (ii) Azeotrope (iii) Osmotic pressure (b) A solution of glucose (C_(6)H_(12)O_(6)) in water is labelled as 10% by weight. What would be the molality of the solution ? (Molar mass of glucose = 180 g mol^(-1))