The ratio of moles of atoms in 12 g of magnesium and 16 g of sulphur will be :

No. of atoms in 16 g of oxygen.

The number of atoms in 0.004g of magnesium will be

The number of atoms in 0.004 g of magnesium is closed to :

The number of atoms in 0.004 g of magnesium is close to

The ratio of mass of 1 mole of sulphur and 10^(23) atoms of sulphur is ______ . ( S = 32)

The number of moles of atoms in "1030g" of Rhodium is "x" times that of moles of Carbon in 60g Carbon, y times that of moles of Magnesium in "48g" of Magnesium and z times that of moles of Rhenium in 465.5g of Rhenium.Then find the value of "(x+y+z)" .Given Atomic mass : Rhodium =103 amu, Rhenium =186.2 amu

28 g of magnesium oxide is produced by the combination of 12 g of magnesium and 16 g of oxygen. Which law is illustrated by this data ?

Calculate the mole ratio of 240 g of calcium and 240 g of magnesium. (Ca = 40 , Mg = 24 u)